How Is ""2" > "10"" "true" in JavaScript?

What is output of ""2">"10"" true or false At first glance, this looks completely wrong. We all know that: 2 > 10 is obviously: false Because 2 is smaller than 10. But what happens when we add quotation marks? "2" > "10" The result is: true 😱 Wait… how can 2 be greater than 10? The answer is simple: ""2"" and ""10"" are not numbers. They are strings. 🔢 Numbers vs. Strings In JavaScript, these two values are different: 2 This is a number. While: "2" This is a string. The quotation marks tell JavaScript that the value should be treated as text. So: 2 > 10 compares two numbers: 2 > 10 → false But: "2" > "10" compares two strings. And that's where things get interesting! 🔤 How Does JavaScript Compare Strings? When JavaScript compares two strings, it uses lexicographical comparison. You can think of this as comparing text in a dictionary-like order, based on the character values. Let's compare: "2" "10" JavaScript looks at the first character of each string: "2" → first character is 2 "10" → first character is 1 Since the character ""2"" comes after ""1"" in the ordering used for the comparison, JavaScript determines: "2" > "10" as: true So: console.log("2" > "10"); outputs: true 🧪 Let's Compare Both Cases Case 1: Numbers console.log(2 > 10); Output: false Because JavaScript compares the actual numerical values: 2 is less than 10 Case 2: Strings console.log("2" > "10"); Output: true Because JavaScript performs a string comparison. The important thing is: 2 → Number "2" → String The quotation marks can completely change how JavaScript interprets the value. ⚠️ What About Mixed Types? Now look at this: console.log("2" > 10); Here, one value is a string and the other is a number. JavaScript handles this differently. In this case, it converts the string ""2"" into a number for the comparison. So the comparison effectively becomes: 2 > 10 The result is: false This is why understanding data types is extremely important when programming. 💡 The Big Lesson These three comparisons